Math, asked by sakshi4310, 11 months ago

Sample Pa
66. The number obtained on rationalising
denominator of
15--2V6 is
(1) 13+ 50
o
3-2
(3) (3 +52)
(13+15)

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Answers

Answered by arshan51
1

3 rd option is correct if it helps u mark me as brainliest


SulagnaRoutray: How do u get the answer
sakshi4310: yes i also want the
sakshi4310: solution
SulagnaRoutray: ya
SulagnaRoutray: I'm getting 5+2√6 as my answer but this option isn't given
sakshi4310: i know the ans it is c, but o want the solution
arshan51: Yah I am sending
arshan51: Please wait
SulagnaRoutray: ok
SulagnaRoutray: plz do it fast
Answered by sivaprasath
2

Answer:

\sqrt{3} + \sqrt{2}

Step-by-step explanation:

Given :

To rationalise the denominator of the fraction \frac{1}{\sqrt{5-2\sqrt{6} } }

Solution :

\frac{1}{\sqrt{5-2\sqrt{6} } }

\frac{1}{\sqrt{3 + 2 - 2(\sqrt{3})(\sqrt{2})}}

\frac{1}{\sqrt{(\sqrt{3})^2 + (\sqrt{2})^2 - 2(\sqrt{3})(\sqrt{2})}}

\frac{1}{\sqrt{(\sqrt{3} - \sqrt{2})^2}}

\frac{1}{\sqrt{3} - \sqrt{2}}}

By taking conjugate & multiplying,

We get,

\frac{1}{\sqrt{3} - \sqrt{2}}} \times \frac{\sqrt{3} + \sqrt{2}}{\sqrt{3} + \sqrt{2}}

 \frac{\sqrt{3} + \sqrt{2}}{(\sqrt{3} - \sqrt{2})(\sqrt{3}+\sqrt{2})}

 \frac{\sqrt{3} + \sqrt{2}}{(\sqrt{3})^2 - (\sqrt{2})^2}

 \frac{\sqrt{3} + \sqrt{2}}{(3 - 2)}

 \frac{\sqrt{3} + \sqrt{2}}{(1)}

\sqrt{3} + \sqrt{2}

\frac{1}{\sqrt{5+2\sqrt{6} } } = \sqrt{3} + \sqrt{2}


sakshi4310: right option is c
sivaprasath: ya
sivaprasath: option c) √3 + √2
SulagnaRoutray: thank u
sivaprasath: : - )
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