Question

Sample Problem 1. A mass of 2 kg lies on a
plane making an angle 30° to the horizontal. Resolve
its weight along and perpendicular to the plane.
Assume g = 10 ms
2​

Answer 1

solution:

mg is the force which is directed towards downward.

angle of inclination=30°

by resolution of vector, we have to components

=mgSin30° and mgCos30°

where mgSin30° is component along the plane and mgCos30° is component perpendicular to plane.

given: m=2kg & g=10ms^-2

mgSin30°= 2×10×1/2=10N

mgCos30°=2×10×√3/2=10√3N