Math, asked by daskaushik0019, 10 months ago

sana has some amount with her she can buy 50 rings or 40 change. She retains 10% of the amount and buy 20 chains and with the balance she buys rings . how many rings did she purchase?​

Answers

Answered by hasannurul
0

Answer:

Step-by-step explanation:

Answered by Anonymous
0

She purchased 20 rings.

• Given data :

She can purchase 50 rings or 40 chains with her total money.

She retained 10% of her total money.

She purchased 20 chains with her remaining money.

• Now,

She can buy,

40 chains by her = 100% money

1 chain by her = 100%/40 money

20 chains by her = 100%/40 × 20 = 50% money.

• So,the budget for ring purchase

= 100% - (Chain price + Retained money)

= 100% - (50%+10%)

= 40% of her money

• Now,

By 100% of her money she can buy = 50 rings

By 1% of her money she can buy = 50/100 rings

By 40% of her money she can buy = 50×40/100 = 20 rings

So,she can buy 20 rings. (Answer)

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