Question

Sand is falling on a conveyor belt at rate of 5kg/s. the extra power required to move the belt with a velocity of 6 m/s is _____ ?

Answer 1

Answer:

The force required to keep the belt moving is equal to the rate of increase of horizontal momentum of the sand.

Or, F = rate of change of mass × velocity change

=> F = (5 kg/s)(6 m/s)

=> F = 30 N

Now,

Power = work done per second

=> P = force × rate of displacement

=> P = Fv = (30 N)(6 m/s)

=> P = 180 W

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Answer 2

Answer:

F = rate of change of mass * velocity change

⇒F=(5kg/s)(6m/s)

⇒F=30N

Now,

Power = work done per second

P = force * rate of displacement

⇒P=Fv=(30N)(6m/s)

⇒P=180W

Explanation:

hope this helps you.