1. In covering a distance of 30 kilometers, Ajit takes 1 hours more than Sanjay. If Ajit doubles his speed,
then he would take half hour less than Sanjay. Ajit’s speed is
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10km/hr is Ajit's speed
Step-by-step explanation:
Let the time taken of Sanjay be x hr
Then, time taken by Ajit will be (x + 1) hr
As we know,
Distance = Speed * Time
From the given condition,
30/x = 30/(x + 1) ...(i)
ATQ, if Ajit doubles his speed;
⇒ 30/{2 * 30/(x + 1)}
⇒ (x + 1)/2hr
Now, (x + 1)/2hr = (x - 1/2) hr
⇒ (x + 1)/2 = (2x - 1)/2
⇒ 2x + 2 = 4x - 2
⇒ 2 + 2 = 4x - 2x
⇒ 2x = 4
⇒ x = 4/2
⇒ x = 2 km/hr
∵ Sanjay takes 2 hours to cover the distance of 30 km
while Ajit takes (2 + 1) = 3 hours to cover 30 km
Speed of Ajit = distance/time = 30/3 = 10 km/hr
Speed of Sanjay = 30/2 = 15km/hr
Learn more: Speed and distance
brainly.in/question/20619648
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