Math, asked by ekta1374, 5 months ago

Sandeep celebrated his birthday on 12 August 1988 on Friday, next time he celebrated his birthday on Friday in which year?​

Answers

Answered by raniisha016
0

Step-by-step explanation:

Sandeep celebrate his birthday in 1995 in Friday.

Answered by vijayhalder031
0

Concept

A year has 365 days and a leap year has 366 days which occurs after every 4 years. And a year with 365 days the same date appears as next weekday in next year and in case of leap year next to next weekday appears on same date.

Given

Sandeep celebrated his birthday on 12 August 1988 on Friday.

To Find

We have to find the year Sandeep will celebrate his birthday on Friday.

Solution

According to the problem,

1988- is a leap year containing 366 days hence in 1989 his birthday will be on Friday +2= Sunday.

1990 contains 365 days hence his birthday will be on Sunday +1= Monday.

1991 contains 365 days hence his birthday will be on Monday +1=Tuesday.

1992 is leap year containing 366 days hence his birthday will be on Tuesday +2= Thursday.

1993 contains 365 days hence his birthday will be on Thursday +1=Friday.

Hence, Sandeep will celebrate his birthday on Friday in the year 1993.

#SPJ3

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