Question

Sandeepbhau Borrowed 120000 rupees from a bank for 4 years at the rate of 8 1/2 p.c.p.a for his son's education. What is the total amount he returned to the bank at the end of that period?

Answer 1

Answer:

P= ₹120000

R= 8 1/2%

T= 4y

A= P(1+R/100)⁴

=120000(1+8×1/2×100)⁴

=120000(208/200)⁴

=120000×208/200×208/200×208/200×208/200

= ₹140383.0272

HOPE THIS HELP

Answer 2

Given: Sandeepbhau borrowed 120000 rupees from a bank for 4 years at the rate of 8 ½ p.c.p.a. for his son's education.

   

To Find: The total amount he returned to the bank at the end of that period.

____

As we know that:

$\dag \; \underline{\boxed{\frak{\orange{Total \; Intrest \; I = \dfrac{P \times T \times R}{100}}}}}$

   

Therefore,

   

$\implies \sf{Total \; Interest = \dfrac{P \times R \times T}{100} }$

$\implies \sf{Total \; Interest = \dfrac{120 \cancel{0} \cancel{0} \cancel{0} \times 85 \times 4}{1\cancel{0} \cancel{0} \times 1 \cancel{0}} }$

$\implies \sf{Total \; Interest = 120 \times 85 \times 4 }$

$\implies \underline{\boxed{\sf{\purple{Total \; Interest = 40800}}}}$

   

As we know that,

$\dag \; \underline{\boxed{\frak{\orange{ Principal +Interest = Amount }}}}$

   

Therefore,

   

$\implies \sf{120000 + 40800 }$

$\implies \underline{\boxed{\sf{\purple{160800 \; rupees }}}}$

   

★ Final Answer:

⇒ The total amount returned to the bank is ₹ 160800.