Math, asked by tavishabatra2, 7 months ago

SANDHYA 'S PRESENT AGE IS FOUR TIMES OF HER DAUGHTER 'S AGE . AFTER 16 YEARS , SHE WILL BE TWICE THE AGE OF HER DAUGHTER'S AGE . WHAT IS THE PRESENT AGE OF SANDHYA'S DAUGHTER


please answer using x only because i am in class 6th so much difficult sums i cant do​

Answers

Answered by utkarshkothari99
7

Answer:

If Daughter's Age = x

Then Sandhya's Present Age = 4x

After 16 Years - Daughter's Age will be x + 16

And Sandhya's Age = 4x + 16

According to question > 4x + 16 = 2 (x+16)

4x + 16 = 2x + 32

2x = 16

x = 8 is the current age of Sandhya's Daughter

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