Sanjay has a fixed monthly salary. There is an yearly increment of a fix amount in the salary. After four years his monthly salary was ₹ 2500 & after ten years his monthly salary became ₹ 3400, find his oriɡinal salary & yearly increment.
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Let the original salary be x and yearly increment be y.
After 4 years, his salary will be Rs.4500
∴x+4y=4500
⇒x=4500−4y.....(1)
After 10 years, his salary becomes 5400.
∴x+10y=5400
⇒4500−4y+10y=5400(From (1))
⇒y=150
Substituting the value of y in equation (1), we have
⇒x=4500−4×150
⇒x=4500−600=3900
Hence, his original salary was Rs.3900 and increment per year is Rs.150
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