Sanjay is half his brothers age. after 6 years Sanjay is three by fifth of his brother age, find both of their ages
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4
age of brothèr =24years snd age of sanjay =12 yrs
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3
let sanjay's brother's age be x then sanjay's age is x/2
after 6 yrs sanjay's brother's age=x+6
therefore sanjay's age becomes=x/2 +6
after 6 yrs sanjay is 3/5 of his brother's age
3/5(x + 6)=x/2+6
=>3x/5+18/5=(x+12)/2
=>(3x+18)/5=(x+12)/2
=>2(3x + 18)=5(x+12)
=>6x+36=5x+60
=>6x-5x=60-36
=>x=24
after 6 yrs sanjay's brother's age=x+6
therefore sanjay's age becomes=x/2 +6
after 6 yrs sanjay is 3/5 of his brother's age
3/5(x + 6)=x/2+6
=>3x/5+18/5=(x+12)/2
=>(3x+18)/5=(x+12)/2
=>2(3x + 18)=5(x+12)
=>6x+36=5x+60
=>6x-5x=60-36
=>x=24
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