Sanjay is now 1/2 as old as his brother. in 6 more years he will be 3/5 as old as his brother then. what is the present age of each boy?
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Answered by
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Let the present age of his brother be x
and present age of Sanjay be x/2
in 6years,
age of his brother be x+6
age of Sanjay be x/2+6
a/q
x/2+6 = 3/5(x+6)
x/2+6 = 3/5x+18/5
x/2-3/5x=18/5-6
-x/10=-12/5
x= 120/5=24
present age of his brother be 24
present age of Sanjay be 12
and present age of Sanjay be x/2
in 6years,
age of his brother be x+6
age of Sanjay be x/2+6
a/q
x/2+6 = 3/5(x+6)
x/2+6 = 3/5x+18/5
x/2-3/5x=18/5-6
-x/10=-12/5
x= 120/5=24
present age of his brother be 24
present age of Sanjay be 12
Msimna777:
what a nice solution
Answered by
23
Answer:
Sanjay brother present age =x
Sanjay age=x/2
in 6 years
Sanjay brother age=x+6
Sanjay age =x/2+6
x/2+6 = 3/5 (x+6)
x/2+6 = 3/5x 18/5
x/2-3/5 = 18/5=6
Crose multiple = -x/10=12/5
X=120/5=24 cut 120 on 5
Sanjay brother age = 24
Sanjay age = 12
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