Math, asked by Msimna777, 1 year ago

Sanjay is now 1/2 as old as his brother. in 6 more years he will be 3/5 as old as his brother then. what is the present age of each boy?

Answers

Answered by Manikumarsingh
80
Let the present age of his brother be x
and present age of Sanjay be x/2

in 6years,

age of his brother be x+6
age of Sanjay be x/2+6

a/q

x/2+6 = 3/5(x+6)

x/2+6 = 3/5x+18/5

x/2-3/5x=18/5-6

-x/10=-12/5

x= 120/5=24

present age of his brother be 24
present age of Sanjay be 12

Msimna777: what a nice solution
Manikumarsingh: thanks
Answered by tinifo
23

Answer:

Sanjay brother present age =x

Sanjay age=x/2

in 6 years

Sanjay brother age=x+6

Sanjay age =x/2+6

x/2+6 = 3/5 (x+6)

x/2+6 = 3/5x 18/5

x/2-3/5 = 18/5=6

Crose multiple = -x/10=12/5

X=120/5=24 cut 120 on 5

Sanjay brother age = 24

Sanjay age = 12

☺☺☺☺

Step-by-step explanation:

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