Question

Sanjeev is twice as old as his son if after four year she will be four times as old as his son was 9 year ago how old is each now

Answer 1

Let the present age of sanjeev's son be X year's.


Present age of sanjeev = 2 ( Present age of his son ) = 2X year's.




After 4 years age of sanjeev = Present age of sanjeev + 4 = ( 2X + 4 ) year's.


After 4 years age of his son = Present age of his son + 4 = ( X + 4 ) year's.




Before 9 year's age of his son = Present age of his son - 9 = ( X - 9 ) year's.


According to question,



After 4 years age of sanjeev = 4 ( age of his son before 9 year's ).



2X + 4 = 4 ( X - 9 )



2X + 4 = 4X - 36



4X - 2X = 4 + 36



2X = 40


X = 20 year's.



Present age of sanjeev's son = X = 20 year's.

Present age of sanjeev = 2X = 40 year's.

Answer 2

$\textbf {Hey there, here is the solution.}$

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STEP 1: Define x:

Let the son be x years old

Sanjeev = 2x

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STEP 2: Find Sanjeev's age 4 years later:

Sanjeev = 2x + 4

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STEP 3: Find his son's age 9 years ago:

Son = x - 9

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STEP 4: Form equation:

After 4 years, she will be 4 times as old has his son 9 years ago

⇒ 2x + 4 = 4(x - 9)

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STEP 5: Solve x:

2x + 4 = 4(x - 9)

2x + 4 = 4x - 36

2x = 40

x = 20

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STEP 6: Find their age:

Son = x = 20 years old

Sanjeev = 2x = 2(15) = 40 years old

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Answer: Sanjeev is 40 years old and his son is 20 years old.

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$\textbf {Cheers}$