Question

Sanjeev walks 3 km north and then, turns left and walks 4 km. Find the shortest distance from the point where he started to the point where he is right now

Answer 1

Sanjeev walks 3 km north and then, turns left and walks 4 km.

So he walks 3km north and 4 km west.

So it forms a right angled triangle Where the shortest path is the hypotenuse.

Shortest distance = h

$h = \sqrt{ {3}^{2} + {4}^{2} } = \sqrt{9 + 16} = \sqrt{25} = 5 \: km$

Shortest distance is 5 km.

Answer 2

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