Question

sanjiv has ₹60 in 10-rupee and 5-rupee coins . If the 10-rupee coins exceed the number of 5 - rupee coins by three , how many coins of each does he have ?

Answer 1

Let the number of 10 rupees coin be 'x'
And 5 rupees coin be' y'
So,
10x + 5y = 60
And number of 10 rupees coins are 3 more than 5 rupees coins
So,
10(y+3) + 5y =60
On solving we get
y=2
So x=5

Answer 2

Answer: He has 2 coins of 5 rupee and 8 coins of 10 rupee.

Step-by-step explanation:

Let the number of 5 - rupee coin be 'x'.

Let the number of 10 - rupee coin be 'x+3'

Amount from 5 rupee coins = 5x

Amount from 10 rupee coins = 10(x+3)

Total amount he has = Rs. 60

According to question, it becomes,

$5x+10(x+3)=60\\\\5x+10x+30=60\\\\15x=60-30\\\\15x=30\\\\x=\dfrac{30}{15}\\\\x=2$

So, he has 2 coins of 5 rupee coin and 5+3 = 8 coins of 10 rupee coin.

Hence, he has 2 coins of 5 rupee and 8 coins of 10 rupee.