Question

Santosh a physical education teacher arranged three groups of 140, 91 and 63 students for the march past. If he arranged the same number of students in each row, find the number of students he arranged in each row.

Please keep the answer simple...

Answer 1

Answer:

7

Step-by-step explanation:

For the march past, PET arranged 3 groups of 140,91 and 63 students.

In order to find the number of students he arranged in each row, we have to find the HCF of those these group of students.

140 = 2 * 2 * 5 * 7

91 = 7 * 13

63 = 3 * 3 * 7

HCF(140,91,63) = 7

Hence, the number of students = 7

#Hope my answer helped you!