Question

sanya has piece of land which is in the shape of rhombus she wants her one daughter and one son to work on the land and produce different crops should why did the land into two equal parts is the perimeter of land is 400 m and one of the diagonals is 160 m how much area each of them will get to their crops

Answer 1

area of rhombus = 1/2×d¹× d²
400 ×2÷160=d²
you get your answer

Answer 2

AnswEr:

Let ABCD be the field in which is divided by the diagonal BD = 160 m into two equal parts.

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Since ABCD is a rhombus of perimeter 400 m. Therefore ,

$\sf\quad{AB=BC=CD=DA}$ =

$\sf\quad\dfrac{400}{4}m=100m$

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Let s be the semi-perimeter of ∆BCD.

Then, $\sf\dfrac{BC+CD+BD}{2}$

s= $\sf\dfrac{BC+CD+BD}{2}$

= $\sf\dfrac{100+100+160}{2}m=180m$

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$\therefore$ Area of ∆BCD

= $\sf\sqrt{180(180-100)(180-100)(180-160)}$ m²

= $\sf\sqrt{180\times\:80\times\:80\times\:20}m^2=4800\:m^2$

Hence, each of the two children will get an area of 4800 m².

#BAL

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