Question

Sarah and Henry share some sweets in the ratio 7:6 . Sarah eats 12 of her sweets and the ratio of sweets left becomes 1:2 . How many sweets did Henry have?

Answer 1

Given :

• Sarah and Henry share some sweets in the ratio 7:6 .

• Sarah eats 12 of her sweets and the ratio of sweets left becomes 1 : 2 .

To Find :

• No sweets did Henry have = ?

Step-by-step explanation :

Ratio of Sarah and Henry = 7:6

Let the number of sweets of Sarah be 7x

Let the number of sweets of Henry be 6x

Sarah eats 12 of her sweets, the ratio becomes 1 : 2.

According to the question :

7x - 12 / 6x = 1/2

On simplifying the above equation, we get,

2(7x - 12 = 6x × 1

14x - 24 = 6x

14x - 6x = 24

8x = 24

x = 24/8

x = 3.

Therefore We get the value of x = 3.

Hence

Sweets with Henry will be, 6x = 6 × 3 = 18

Answer 2

${\underline{\huge{\mathbf{\color{pink}{♡Heya\:dost♡}}}}}$

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Given :-

Ratio of sweets sarah and henry have = 7:6

If :

sarah eats 12 sweets ratio become = 1:2

To find :-

number of sweets henry have = ??

Step by step explanation :-

let the ratio be 7x and 6x

ATQ :-

$\frac{7x-12}{6x} = \frac {1}{2}$

$2(7x-12)= 6x$

$14x - 24 = 6x$

$14x-6x = 24$

$8x = 24$

$x = \frac{24}{8}$

$x = 3$

No. of sweets henry have = 6x = 6*3 = 18 sweets

Answer :-

No. of sweets henry have = 18

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