Math, asked by dekuandtodoaremyfav, 10 days ago

sarah is 4 times old as her friend emily. after 16 years, she will only be twice as old as emily. their present ages are : sarah=32 yrs emily= 8 years
what would be the solution to find their present ages if it wasnt given?
answer only if you know. best answer gets brainiliest

Answers

Answered by dkchakrabarty01
1

Answer:

Let present age of Sarah be S and that of Emily be E. Then it is given

S=4×E equation 1

After 16 years Sarah will be S+16 and Emily will be E+16. Again it is given

(S+16)=2×(E+16)

S=2E+16 equation 2

Put the values of S from equation 1 in equation 2

4E=2E+16

2E=16

E=16/2=8

Put this value of E in equation 1, you will get

S=4×8=32

Answered by zohrafirdouse
1

Step-by-step explanation:

Hope this helps

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