Math, asked by ishawarikhedkar, 9 months ago

Sarthak present ages X years and sakshi's present age is y years. The sum of present ages of Sarthak and Sakshi is 25. Sarthak Age is less by 8 then double the age of Sakshi. 4 years ago Sakshi age was three years less than sarthak's age at that time. Find their present ages.​

Answers

Answered by Silverness
64

Answer:

Step-by-step explanation:

x + y = 25

x = 2y - 8

subtracting

y = 25 -2y + 8

3y = 33

y =11 years

x = 25 - y = 25 -11 = 14 years

Thus, Sarthak's present age is x = 14 yrs and Sakshi's is y = 11 years.

Note: These values will satisfy third condition. You can pick any two conditions, frame equations for them and solve.

Answered by rathodniraj2005
25

Step-by-step explanation:

x+y=25

x-y=3

add above equation

2x=28

x=14

put this value in equation

x+y=25

14+y=25

y=25-14

y=11

(x, y) =(14,11)

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