Question

sarvan father is three times as old as sarvan . sum of their age is 56 years .take sarvan's age as x years​

Answer 1

Given :

• Sarvan's father age is three times the age of Sarvan .
• Sum of their ages is 56 .

To Find :

• Ages of both .

Solution :

$\longmapsto\tt{Let\:age\:of\:Sarvan\:be=x}$

As Given that Sarvan's father age is three times the age of Sarvan . So ,

$\longmapsto\tt{Age\:of\:father=3x}$

A.T.Q :

$\longmapsto\tt{x+3x=56}$

$\longmapsto\tt{4x=56}$

$\longmapsto\tt{x=\cancel\dfrac{56}{4}}$

$\longmapsto\tt\bf{x=14}$

Value of x is 14 .

Therefore :

$\longmapsto\tt{Age\:of\:Sarvan=x}$

$\longmapsto\tt\bf{14\:yrs}$

$\longmapsto\tt{Age\:of\:his\:father=3(14)}$

$\longmapsto\tt\bf{42\:yrs}$

Answer 2

${ \huge{ \boxed{ \bf{\underline{ \red{Answer}}}}}} : -$

Let Servan Age is x.

Then ,

There father age is tree times old as servan.

x + 3x = 56

4x = 56

Now we Divide ,

$x \: = \: \frac{56}{4}$

therefore x = 14

Mean Servan age is 14 years.

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Hope it's Helpful :)