Question

(SAT Prep) Find the value of x in each of the following exercises:

Answer 1

x = 115° will be the answer.

Step-by-step explanation:

From the figure attached,

DB║EF and DE is a transverse.

Therefore, BDE = 180 - x [ Internal angles of the parallel lines and transverse are supplementary.

Similarly, BF║DE and BD is a transverse.

Therefore, ∠DBF = 180- (180 - x) = x°

Now ∠ABC = (180 - x)°

In ΔABC,

∠ABC + ∠BCA + ∠CAB = 180°

(180 - x) + (180 - x) + 50 = 180

410 - 2x = 180

2x = 410 - 180

2x = 230

x = $\frac{230}{2}=115$

Therefore, x = 115° will be the answer.

Learn more about the properties of parallel lines from https://brainly.in/question/7592870