Question

satellite of mass m is revolving round the earth at a height R above the surface of earth. If g is gravitational acceleration at surface of earth and R is radius of earth then magnitude of momentum of satellite is?​

Answer 1

$\huge\underline\bold\orange{♡Question♡}$

satellite of mass m is revolving round the earth at a height R above the surface of earth. If g is gravitational acceleration at surface of earth and R is radius of earth then magnitude of momentum of satellite is?

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$\mathsf\red{Step \: by \: step \: explanation: - \:}$

At a height h, acceleration due to gravity be g

As, g ′ =g(1+ Rh) −2

Now, for h=R,⟹g ′ = 4g

potential energy, P.E=−

(R+h)GMm , and g ' = (R+h) 2GM⟹P.E=−mg ′ (R+h)

For h=R,P.E=−m× 4g×2R

Thus, P.E=− 2mgR

Answer 2

Answer:

As orbital velocity of satellite, v=

r

GM

where r=R+h

So, angular momentum L=mvr=m[

r

GM

]r

⟹L=m

GM(h+R)

i.e, L depends on m,M,h.