Question

Satpal walks 2/3 km from a place P towards east and then from there 1 5/7 km towards west. Where will he be now from P?

Answer 1

He will be 1.47 km towards east from p Ans= 15/7-2/3= 31/21= 1.47

Answer 2

The Current Position of Satpal is $\frac{22}{21} \ km$ OR  $1\frac{1}{21} \ km$ from P towards west.

Step-by-step explanation:

Given:

Satpal Walks from P towards east = $\frac{2}{3}\ km$

Now from that point towards west = $1\frac{5}{7}\ km$

$1\frac{5}{7}\ km$ can be Rewritten as  $\frac{12}{7}\ km$

Hence

Now from that point towards west =  $\frac{12}{7}\ km$

We need to find the current Position from P.

SO to find the current Position we will Subtract from that point towards west with from P towards east.

framing in equation form we get;

current Position = $\frac{12}{7}-\frac{2}{3}$

Now taking LCM to make the Denominator common we get;

current Position = $\frac{12\times3}{7\times3}-\frac{2\times7}{3\times7}= \frac{36}{21} -\frac{14}{21} = \frac{36-14}{21}= \frac{22}{21} \ km$

$\frac{22}{21} \ km$ can be written in Mixed fraction as  $1\frac{1}{21} \ km$

So The Current Position of Satpal is $\frac{22}{21} \ km$ OR  $1\frac{1}{21} \ km$ from P towards west.