Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60 km/h?
Answers
Answered by
12
WD = KE = mv²/2
= 1500 * 60 * 5/18 * 60 * 5/18 / 2
= 1500 * 16 * 16/2
= 192000J
= 1500 * 60 * 5/18 * 60 * 5/18 / 2
= 1500 * 16 * 16/2
= 192000J
Dhanush2001:
y did u multiply 5/18 twice rather than once
Answered by
4
work done= -1/2mv^2
-1/2*1500*5/18*60
-208416.675
-1/2*1500*5/18*60
-208416.675
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