saumya thinks of a number and subtractor ' r ' from it.she multiplies the result by ' p ' the result now obtained is ' N ' times the number she thought of.find the number she thought of.if (a)r = 7 / 2, p = 10, N = 3
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number she thought = x
p(x - r) = nx
10(x-7/2) = 3x
10x - 70/2 = 3x
10x - 3x = 70/2
7x = 35
x= 35/7
x = 5
therefore, the number she thought of is 5.
p(x - r) = nx
10(x-7/2) = 3x
10x - 70/2 = 3x
10x - 3x = 70/2
7x = 35
x= 35/7
x = 5
therefore, the number she thought of is 5.
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