Math, asked by maureenfalke40, 10 months ago

. Saurabh started from place A and went to place B at a distance of 56 m due
east. From there he went to place C at a distance of 105 m due north. What is
the minimum distance between the places A and C? ​

Answers

Answered by ayush352821
5

Hope it helps you. Good Morning

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Answered by RitaNarine
1

The minimum distance between the places A and C is  119m

GIven Saurabh started at point A went to B at a distance of 56m due east.

Now he turns left and goes north by 105m.

Now the shortest distance between A and C will be the hypotenuse of the right angles triangle ABC, right angled at B.

AC = \sqrt{AB^{2} + BC^{2}  } = \sqrt{56^{2}  + 105^{2} }

AC = \sqrt{3136 + 11025} = \sqrt{14161} = 119m

This can also be visualized as the triangle law,

Where the third side is always smaller than sum of the other two sides.

  • ie, AB < AC + BC
  •   AC < AB + BC
  •   BC < AC + AB

Therefore the shortest distance between the start and the end point is 119m.

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