. Saurabh started from place A and went to place B at a distance of 56 m due
east. From there he went to place C at a distance of 105 m due north. What is
the minimum distance between the places A and C?
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The minimum distance between the places A and C is 119m
GIven Saurabh started at point A went to B at a distance of 56m due east.
Now he turns left and goes north by 105m.
Now the shortest distance between A and C will be the hypotenuse of the right angles triangle ABC, right angled at B.
AC = =
AC = = = 119m
This can also be visualized as the triangle law,
Where the third side is always smaller than sum of the other two sides.
- ie, AB < AC + BC
- AC < AB + BC
- BC < AC + AB
Therefore the shortest distance between the start and the end point is 119m.
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