Question

Saurav starts from a definite point and moves towards East travelling a distance
of 2 m. Then, he turns to right and travels 5 m. From here he turns to right and
travels 8 m. Finally, he turns to right and moves 13 m. How far is he now from his
starting point?​

Answer 1

Step-by-step explanation:

east-2m

turns right 5m

turns right 8m

turns right 13 m

so using displacement formula answer is 9m

if the ans is satisfactory mark brainliest

Answer 2

Saurav is 10m away from his starting point.

Step-by-step process:

We need to find the distance between the starting and the ending point. Let us consider A as the start point and E as Saurav's final position as shown in the figure.

Since he moves in a straight line:

BC= FD

So, EF= ED-FD

EF= 13-5= 8m

Now, BF= CD

SO AF= BF-AB

AG= 8-2= 6m

Now that we know the values of EF and AF, we can find AE by Pythogoras theorem.

$AE^{2} =\sqrt{EF^{2 } +AF^{2}$

Putting in the values:

$AE^{2} = \sqrt{8^{2}+ 6^{2} }$

$AE^{2}$= $\sqrt{64 +36}$

$AE^{2}$= $\sqrt{100}$

AE= 10m

Result:

Thus, Saurav is 10m away from his starting point.

(#SPJ3)