Question

savita has Rs 27 in the form of fifty paise and twenty five paise coins. she has twice as many as twenty five coins as she hai fifty paise cions. how many coins of each kind does she have? form an equation and answer in formula

Answer 1

Solution:-
Let the number of 50 paise coins Savita has = x 
So, the total value in rupees = 50 × x = 50x Rs.
Therefore, the number of 25 paise coins Savita will have = 2x because it is twice as many as 50 paise coins.
So, the total value in rupees = 25 × 2x = 50x
Total Money = 27 Rs or 2700 paise
Now, according to the question
50x + 50x = 2700
100x = 2700
x = 27
So, the number of 50 paise coins Savita has = 27 coins
The number of 25 paise coins she has = 2 × 27 = 54 coins.
Answer

Answer 2

Solution:

Let the actual number of 50 paisa coins, Savita has can be assumed as x

So, the overall worth in rupees $=50 \times x = 50x$

Therefore, the amount of 25 paisa coins Savita can have = 2x (as a result of, it is double as several as paisa coins).

So, the total number of value in rupees $=25 \times 2x=50x$

Total Money = 27 Rupees or 2700 paisa

Now, according to the question,

$\Rightarrow \text$ { (Amount of Money in 50 paisa coins) $\times$ (Amount of Money in 25 paisa coins) } =2700

$\Rightarrow$ 50x + 50x = 2700

$\Rightarrow$ 100x = 2700

$\Rightarrow$ x=27

So, the number of 50 paisa coins Savita has = 50x

= (27) 50 = 54 coins

Amount of 50 paisa coins Savita has = 13.5 rupees

The number of 25 paisa coins = 50x

The amount of 25 paisa coins = 50 (27) = 54 coins

Amount of 25 paise coins Savita has = 13.5 rupees

Total money Savita = 13.5 rupees + 13.5 rupees = 27 rupees