Question

say the answer please​

Answer 1

Answer:

$\huge\colorbox{yellow}{Answer\:-}$

$\small\underbrace\mathrm\red{First \: Equation}$

${20l}^{2}m + 30alm$

${20l}^{2} m = 2 \times 2 \times 5 \times 1 \times 1 \times m$

$30alm = 3 \times 2 \times 5 \times a \times l \times m$

The two terms have 2,5,1 and m as common factors

${20l}^{2} m + 30alm = (2 \times 2 \times 5 \times 1 \times 1 \times m) + (3 \times 2 \times 5 \times a \times l \times m)$

$= 2 \times 5 \times 1 \times m \times (2 \times 1 \times + 3 \times a)$

$= 10lm(21 + 3a)$

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Answer 2

QUESTION 1:

20l²m+30alm

10lm(2l+3a)

QUESTION 2 :

5x²y - 15xy²

5xy(x-3y)

QUESTION 3:

x²yz+xy²z+xyz²

xyz(x+y+z)

hope it helps

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