school teacher please answer this question please
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Distance=2πr =2×22/7×5=220/7=31.42m (approx)
Speed=Distance/Time=31.42/12=2.6m/s(approx(
Displacement=Diameter of track=2r=5×2m=10m
Velocity=Displacement/Time=10/12m/s=0.8m/s (approx)
Explanation:
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