Question

se ti
(1) X+1
2
Find the remainder when x-ar? + 6x-a is divided by X-a.
by long devision​

Answer 1

Step-by-step explanation:

Here, p(x)=x

3

+ax

2

+6x−a, and the zero of x−a is a

So, p(a)=a

3

+a×a

2

+6×a−a

=2a

3

+5a

So, by the Remainder Theorem, 2a

3

+5a is the remainder when x

3

+ax

2

+6x−a is divided by x−a.