Question

sea water contains 53 ppm of Na2Co3 . Find mass of Na2Co3 present in water

Answer 1

Answer:

Explanation:

ppm=mass of solute/volume of solution multiplied by 10^6

here 53 ppm indicate 53g of na2co3 in 1000ml

Answer 2

The given question is incomplete. the complete question is :

Sea water contains 53 ppm of Na2Co3 . Find mass of Na2Co3 present in 100 g of water.

The mass of $Na_2CO_3$ present in water is $5.3\times 10^{-3}g$

Explanation:

Concentration in ppm =$\frac{\text {mass of solute}}{\text {mass of solution}}\times 10^6$

Given ; Concentration in ppm = 53

mass of solute $Na_2CO_3$ = x g

Mass of solution = mass of solute $Na_2CO_3$  + mass of water = x g + 100 g

$53=\frac{x}{(x+100)}\times 10^6$

$x=5.3\times 10^{-3}g$

Thus the mass of $Na_2CO_3$ present in water is $5.3\times 10^{-3}g$

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