Math, asked by abhishekmishra0, 10 months ago

sec ( 1 -sin) (sec+ tan) =1​

Answers

Answered by radhu66
1

Answer:

sec(1-sin)(sec+tan)=1

1/cos(1-sin) (1/cos+sin/cos)=1

1/cos(1-sin) (1+sin/cos)=1

1/cos(1-sin) (1+sin)/cos=1

1/cos²(1-sin²)=1

1-sin²/cos²=1

cos²/cos²=1

1 =1

Answered by kananverma74
0

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