Question

sec 17/cosec 73+ tan 68/cot 22+cos^2 44+cos^2 46

Answer 1

$\frac{ \sec17}{ \csc73 } + \frac{ \tan68}{ \cot22 } + { \cos }^{2}44 + { \cos }^{2} 46 \\ \\ \frac{ \sec17 }{ \csc(90 - 17) } + \frac{ \tan68 }{ \cot(90 - 68) } + { \cos }^{2}44 + { \cos(90 - 44) }^{2} \\ \\ \frac{ \sec17 }{ \sec17 } + \frac{ \tan68 }{ \tan68 } + { \cos }^{2} 44 + { \sin }^{2} 44 \\ \\ \\ we \: know \: that \: ....... \\ \\ \csc(90 - \alpha ) = \sec\alpha \: \\ \\ cot(90 - \alpha ) = \tan\alpha \\ \\ ans \: cos(90 - \alpha ) = \sin\alpha \\ \\ 1 + 1 + 1 = 3 \\ \\ we \: know \: that......sin^{2} \alpha + { \cos}^{2} \alpha = 1$

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Answer 2

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