Question

sec^2 30 degree - tan^2 30 =degree ​

Answer 1

Step-by-step explanation:

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Answer 2

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To know:

values: sec 30°=

$\frac{2}{ \sqrt{3} }$

tan30°=

$\frac{1}{ \sqrt{3} }$

so according to question

$sec^{2} 30 - {tan}^{2} 30 \\ (\frac{2}{ \sqrt{3} } )^{2} - ( \frac{1}{ \sqrt{3} } )^{2}$

$= \frac{4}{3} - \frac{1}{3} \\ = \frac{4 - 1}{3} \\ = \frac{3}{3}$

$1$

$tan45 \: degree$