Question

√(sec^2 P + cosec^2 P) is equal to (root is in the whole expression)


cos P + sin P

tan P + cot P

tan P

cot P​

Answer 1

Answer:

Answer

L.H.S=(cscp−sinp)(secp−cosp)(tanp+cotp)

=(

sinp

1

−sinp)(

cosp

1

−cosp)(

cosp

sinp

+

sinp

cosp

)

=(

sinp

1−sin

2

p

)(

cosp

1−cos

2

p

)(

sinpcosp

sin

2

p+cos

2

p

)

=(

sinp

cos

2

p

)(

cosp

sin

2

p

)(

sinpcosp

1

) by cancelling the like terms

=1

=R.H.S

Hence proved

Step-by-step explanation:

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Answer 2

Answer:

Hi dear I am Aayush Malik