√(sec^2 P + cosec^2 P) is equal to (root is in the whole expression)
cos P + sin P
tan P + cot P
tan P
cot P
Answers
Answered by
1
Answer:
Answer
L.H.S=(cscp−sinp)(secp−cosp)(tanp+cotp)
=(
sinp
1
−sinp)(
cosp
1
−cosp)(
cosp
sinp
+
sinp
cosp
)
=(
sinp
1−sin
2
p
)(
cosp
1−cos
2
p
)(
sinpcosp
sin
2
p+cos
2
p
)
=(
sinp
cos
2
p
)(
cosp
sin
2
p
)(
sinpcosp
1
) by cancelling the like terms
=1
=R.H.S
Hence proved
Step-by-step explanation:
mark as brainliest pls
Answered by
0
Answer:
Hi dear I am Aayush Malik
Similar questions