Question

sec ²nx
sinn-
eseca
o
O
cot 2x seen-
T
1+ sinu​

Answer 1

Answer

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Let △ABC be right angled triangle (right angled at B)

secQ=ABAC=1213

Let AC=13x and AB=12x

AC2=AB2+BC2

BC2=AC2−AB2

x2=169−144

x2=25

x=25=5

sinQ=ACBC=13x5x=135  

cosQ=ACAB=1312

tanQ=ABBC=12x5x=125

cotQ=tanQ1<