Question

Sec^2teta+cosec^2tete=sec^2teta×cosec^2teta

Answer 1

Answer: Sec²θ +cosec²θ = sec²θ × cosec²θ

LHS-  = Sec²θ +cosec²θ

         = 1/cos²θ + 1/sin²θ

         = (sin²θ + cos²θ) ÷ cos²θ x sin²θ

        Using identity sin²θ + cos²θ =  1

         = 1/cos²θ x sin²θ

        ( Separating the terms)

        = 1/cos²θ x 1/sin²θ

        = sec²θ × cosec²θ

Therefore LHS=RHS, hence proved!!

HOPE THIS HELPS!!