Math, asked by nancyinsan482, 11 months ago

Sec^2x ×cosec^2x =sec^2x +cosec^2x

Answers

Answered by swetarani402
2

Answer:

sec²x×cosec²x=sec²x+cosec²x

LHS=sec²x×cosec²x

1/cos²x×1/sin²x=1/cos²x×sin²x

=1/cos²xsin²x

RHS=sec²x+cosec²x

1/cos²x+1/sin²x=(sin²+cos²x)/cos²x×sin²x

=1/cos²xsin²x (sin²x+cos²x=1)

Therefore,

LHS=RHS=1/cos²xsin²x

proved

Step-by-step explanation:

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