Question

The difference of twice the smaller of the consecutive integers and the larger is 39. Find the integers

Answer 1

Answer:

s=40

b=41

2s-b=39

b-s=1

b=1+s

2s-(1+s)=39

s-1=39

s=39+1

s=40

Answer 2

Let the three numbers be: x-1, x and x+1.

-Therefore, x-1 + x + x+1 =3x = 39

-Hence x, the middle number is 13.

-The other two numbers are 12 and 14.