sec(45+A)+sec(45-A)= ?
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Answered by
2
sec(45+A)+sec(45-A)= cosec(90-45-A)
+sec(45-A)
= cosec(45-A)+sec(45-A)
+sec(45-A)
= cosec(45-A)+sec(45-A)
sreeram949p88ss6:
sec(45+A) sec(45+A) = ?
sec(45-A)*
I don"t know Sorry
is the question correct?
thank you so much for spending your precious time for me
yeah !! the question is correct
I regret I could not help you thoroughly
Answered by
5
Answer:
2sec2A
Step-by-step explanation:
sec(45° + A) . sec(45° - A) = 2sec2A
1/cos(45° + A) . 1/cos(45° - A) = 2 × 1/cos2A
2cos(45° + A). cos(45°-A) = cos2A
LHS = 2cos(45° + A) . cos(45° - A)
= cos[(45° + A) + (45° - A) ] + cos[(45° + A) - (45° - A) ]
= cos90° + cos(45° + A - 45° + A)
= cos2A
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