Math, asked by sreeram949p88ss6, 1 year ago

sec(45+A)+sec(45-A)= ?

Answers

Answered by ishasood13

sec(45+A)+sec(45-A)= cosec(90-45-A)
+sec(45-A)
= cosec(45-A)+sec(45-A)

sreeram949p88ss6: sec(45+A) sec(45+A) = ?

sreeram949p88ss6: sec(45-A)*

ishasood13: I don"t know Sorry

ishasood13: is the question correct?

sreeram949p88ss6: thank you so much for spending your precious time for me

sreeram949p88ss6: yeah !! the question is correct

ishasood13: I regret I could not help you thoroughly

Answered by Swarnimkumar22

2sec2A

sec(45° + A) . sec(45° - A) = 2sec2A

1/cos(45° + A) . 1/cos(45° - A) = 2 × 1/cos2A

2cos(45° + A). cos(45°-A) = cos2A

LHS = 2cos(45° + A) . cos(45° - A)

= cos[(45° + A) + (45° - A) ] + cos[(45° + A) - (45° - A) ]

= cos90° + cos(45° + A - 45° + A)

= cos2A

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