Question

Sec^4A-sec^2A= tan^4A+tan^2A​

Answer 1

sec2A=1+tan2A LHS = sec4A−sec2A =(sec2A)2−sec2A =(1+tan2A)2−(1+tan2A) =1+2tan2A+tan4A−1−tan2A =tan4A+tan2A = RHS

=sec-4a-sec-2a-tan-4a-tan-2a

Answer 2

Answer:

LHS:

sec⁴A-sec²A=sec²A(sec²A-1)

(1+tan²A).tan²A

tan⁴A+tan²A

using identity;

sec²@-1=tan²@