Math, asked by hanumanthraju26340, 2 months ago

sec^4A-tan^4A = 1+2sin^2A​

Answers

Answered by pavanigandla1428
1

I will do it today

because I don't know the answer

and iam sorry

Answered by abhilashkotha
1

Answer:

sec^4A - tan^4A

= (sec^2A)^2 - (tan^2A)^2

= (sec^2A - tan^2A)(sec^2A + tan^2A)

= 1((sec^2A + tan^2A)

= (sec^2A + tan^2A)

= 1/cos^2A + sin^2A/Cos^2A

= (1+sin^2A)/cos^2A

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