Question

sec^6 theta = tan ^6 theta +3 tan² theta . sec² theta +1​

Answer 1

Answer:

hiiiiii mate here is ur solution..

(above attachment)

hope it's helpful

Answer 2

Step-by-step explanation:

Recall that 1 + tan^2x = sec^2x and A3-B3 = (A-B)(A2+AB+B2)

sec^6x - tan^6x = (sec^2x)3 - (tan^2x)3

= (sec^2x - tan^2x)(sec^4x + sec^2xtan^2x + tan^4x)

= (1+tan^2x-tan^2x))[sec^4x+sec^2xtan^2x+(sec^2x-1)tan^2x]

= sec^4x - tan^2x + 2sec^2xtan^2x

= sec^2x(1+tan^2x) - tan^2x + 2sec^2xtan^2x

= sec^2x - tan^2x + sec^2xtan^2x + 2sec^2xtan^2x

= 1 + 3sec^2xtan^2x

i had x in place of theta