Question

Sec^6 theta = tan^6 theta+3tan square theta sec square theta +1

Answer 1

So here is the answer...

Answer 2

Answer:

L.H.S = R.H.S

Step-by-step explanation:

In this question

Given that

$sec^6 \Theta$ = $tan^6 \Theta+3 tan^2 \Theta sec^2 \Theta + 1$

Let L.H.S

$sec^6 \Theta$

$(sec^2 \Theta)^3$

$(1 + tan^2 \Theta)^3$

Formula, $(a + b)^3$ = $a^3 + b^3 + 3ab(a + b)$

$1 + tan^6 \Theta + 3 tan^2 \Theta (1 + tan^2 \Theta)$

$1 + tan^6 \Theta + 3 tan^2 \Theta (sec^2 \Theta)$

$1 + tan^6 \Theta + 3 tan^2 \Theta sec^2 \Theta$

R.H.S