Math, asked by Ribi, 1 year ago

sec^6A-tan^6A=1+3tan^2A+3tan^4A

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Answered by ayushchoubey

20

your answer is
$1 + 3 { \tan(a) }^{2} + 3 { \tan(a) }^{4}$

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Answered by Simran1203

8

Answer:

Hope it helps

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