Math, asked by 890ROSHAN, 11 months ago

Sec(90°-ø).cosec ø-tan (90°-ø)cotø+cos2 25°+cos2 65°
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3tan 27°tan 63°

Answers

Answered by sneha2727
1

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Answered by krishnmnaik
2

Step-by-step explanation:

sec(90-©)=cosec©

tan(90-©)=cot©

cos²25=sin²(90-25)=sin²65

tan 27= cot(90-27)=cot 63

cosec©.cosec ©- cot©.cot©+sin²65+cos²65/3.cot63.tan63

cosec²©- cot²©+1/3*1 (sin²©+cos²©=1)

1+1/3 (cosec²©- cot²©=1)

2/3.

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