Question

sec(90°-Q )x cosecQ-tan(90°-Q)cotQ +cos²25° +cos 65°
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3 tan27° x tan63°

Answer 1

sec(90- Q) = cosec Q

tan (90-Q) = cot Q.

cos 65 = cos(90-25) = sin 25

So cosec^2 Q - cot^2 Q + cos^25 + sin^25

1 + 1 = 2


3 tan ( 90-63) tan 63

3 cot 63 tan63

3