Question

Sec A (1 - sec A) (secA+tan A) = 1​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

according to question :-

sec A (1-sec A) (sec A + tan A) = 1

1/cos A (1-1/cos A) (1/cos A + sin A / cos A) = 1

1/cos A (cos A - 1 / cos A) (1+sin A / cos A) = 1

1/cos A * cos A -1 / cos A * 1+sin A / cos A = 1

cos A -1 / cos A ^3 = 1

cos A / cos A ^3 = 1+1

1/ cos A ^2 = 2

1 = 2 * cos A ^2

1 = 2cos A ^2

1/2 = cos A ^2

√1/2 = cos A

cos 60 degree = cos A

A = 60 degree

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