Question

sec A (1 – sin A) (sec A + tan A) = 1​

Answer 1

Answer:

Step-by-step explanation:

L.H.S=secA(1−sinA)(secA+tanA)=(secA−  sinA /cosA  )(secA+tanA)

=(secA−tanA)(secA+tanA)

=sec  ^2  A−tan  ^2  A

Putting if tan  ^2  A+1=sec  ^2  A−

we get L.H.S=1+tan  ^2  A−tan  ^2 A=1

⇒L.H.S=R.H.S

Answer 2

Answer:

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